(-18x^2+60x-50)=0

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Solution for (-18x^2+60x-50)=0 equation: 



(-18x^2+60x-50)=0

We get rid of parentheses

-18x^2+60x-50=0

a = -18; b = 60; c = -50;
Δ = b2-4ac
Δ = 602-4·(-18)·(-50)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-60}{-36}=1+2/3$

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